Someone please help ASAP
a(x) = 7x^2+4x-5,
and b(x) = x - 4

Answer:
7x + 32 and 123
Step-by-step explanation:
One way to divide is to use the divisor as a factor in the numerator
Consider the numerator
7x(x - 4) + 28x + 4x - 5
= 7x(x - 4) + 32(x - 4) + 128 - 5
= 7x(x - 4) + 32(x - 4) + 123
quotient = 7x + 32 and remainder = 123
[tex]\frac{7x^2+4x-5}{x-4}[/tex] = x + 32 + [tex]\frac{123}{x-4}[/tex]