Respuesta :

The give compound is a sparingly soluble salt, [tex]Zn_{3}(PO_{4})_{2}[/tex]. The solubility equilibrium for this compound can be represented as:

                 [tex]Zn_{3}(PO_{4})_{2}(aq)<==>3Zn^{2+}(aq)+2PO_{4}^{3-}(aq)[/tex]

Initial(M)                      -                            0                   0

Change(M)                 -                          +3x                +2x

Equilibrium(M)            -                           3x                  2x


Solubility product expression for this equilibrium will be:

[tex]K_{sp}=[Zn^{2+}]^{3}[PO_{4}^{3-}]^{2}[/tex]

              = [tex](3x)^{3}(2x)^{2}=108x^{5}[/tex]

Where x will be the molar solubility of the compound[tex]Zn_{3}(PO_{4})_{2}[/tex]at that given temperature.

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