Question

Identify the compound with the smallest percent ionic character. identify the compound with the smallest percent ionic character. hf lif ibr hcl

Answer 1

Answer: IBr has the smallest percentage ionic character amongst the given compounds.

Explanation: Percentage ionic character is calculated by using the formula:

$\%\text{ Ionic character}=[16(\Delta E.N.)+3.5(\Delta E.N.)^2]\%$    ....(1)

where, $\Delta E.N.$ = difference in the electronegativies of the element forming a compound.

Electronegativity of H = 2.1

Electronegativity of F = 3.98

Electronegativity of Li = 0.98

Electronegativity of I = 2.66

Electronegativity of Br = 2.96

Electronegativity of Cl = 3.16

• For HF

$\Delta E.N.=3.98-2.1=1.88$

Putting this in equation 1, we get:

$\%\text{ Ionic character of HF}=[16(0.188)+3.5(1.88)^2]=42.45\%$

• For LiF

$\Delta E.N.=3.98-0.98=3.00$

Putting this in equation 1, we get:

$\%\text{ Ionic character of HF}=[16(3)+3.5(3)^2]=79.5\%$

• For IBr

$\Delta E.N.=2.96-2.66=0.30$

Putting this in equation 1, we get:

$\%\text{ Ionic character of HF}=[16(0.30)+3.5(0.30)^2]=5.115\%$

• For HCl

$\Delta E.N.=3.16-2.1=1.06$

Putting this in equation 1, we get:

$\%\text{ Ionic character of HF}=[16(1.06)+3.5(1.06)^2]=20.89\%$

From the above calculations, we see that IBr has the smallest percent ionic character.

Answer 2

IBr will have the smallest percent ionic character because it is largely covalent.

The percentage ionic character of a compound tells us whether the compound is ionic or covalent. Ideally, no compound is completely ionic or covalent. The real bonding situation is always somewhere between the two extremes.

Looking at the compounds, we can see that the compound IBr will have the smallest percent ionic character because it is largely covalent.

Learn more about ionic character:https://brainly.com/question/12978582