Respuesta :
Given:
Volume of the tank (V) = 265 gallons
Mass of methane = 88.5 kg
Temperature T = 42 C
To determine:
The pressure P in the tank
Explanation:
From ideal gas law:
PV = nRT ----(1)
where P = pressure, V = volume, n = moles, R = gas constant = 0.0821 L.atm/mol-K and T = temperature
Based on the given data
V = 265 gal = 1003.13 L
T = 42 + 273 = 315 K
moles of CH4 (n) = mass of CH4/molar mass = 88.5/16 = 5.531 moles
Based on eq (1) we have:
P = nRT/V = 5.531 * 0.0821*315/1003.13 = 0.143 atm
Ans: The tank pressure is 0.143 atm
Answer : The pressure inside the tank is 142.6 atm
Explanation:
Using ideal gas equation:
[tex]PV=nRT\\\\PV=\frac{w}{M}RT[/tex]
where,
P = pressure of gas = ?
V = volume of gas = [tex]265\text{ gallon}=1003.025L[/tex]
conversion used : [tex](1\text{ gallon}=3.785L)[/tex]
T = temperature of gas = [tex]42^oC=273+42=315K[/tex]
R = gas constant = 0.0821 L.atm/mole.K
w = mass of methane gas = 88.5 kg = 88500 g
M = molar mass of methane = 16 g/mole
Now put all the given values in the ideal gas equation, we get:
[tex]P\times (1003.025L)=\frac{88500g}{16g/mole}\times (0.0821L.atm/mole.K)\times (315K)[/tex]
[tex]P=142.6atm[/tex]
Therefore, the pressure inside the tank is 142.6 atm
