Question

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Answer 1

Answer:

indirect variation

Step-by-step explanation:

Lets take first two columns and check

When x=5 , y =2

When x= 10, y = 1

Lets check with direct variation, y =kx

When x=5 , y =2

2 = 5k

 $k= \frac{2}{5}$

Now we check whether we get y=1 when x=10

y=kx

$y= \frac{2}{5}*10$

y=4

So given table is not a direct variation

Lets check with direct variation, y =k/x

When x=5 , y =2

$2 = \frac{k}{5}$

k = 10

Now we check whether we get y=1 when x=10

$y = \frac{10}{x}$

$y = \frac{10}{10}$

y=1

we Check with one more value

from the table , x=20, y=1/2

$y = \frac{10}{x}$

$y = \frac{10}{20}$

So $y = \frac{1}{2}$

Hence given table is a indirect variation

Equation is $y = \frac{10}{x}$