Given:
Volume of gas = 215 ml
Initial temperature T1 = 20C = 20 +273 = 293 K
Initial pressure P1 = 1 atm
Final pressure P2 = 1.5 atm
To determine:
The final temperature T2
Explanation:
Based on Gay-Lussac's Law:
P α T
Therefore we have the relation:
P1/T1 = P2/T2
T2 = P2T1/P1 = 1.5 *293/1 = 439.5 K
Converting from Kelvin to degrees C we have:
T2 = 439.5 - 273 = 166.5 C
Ans: The final temperature is 439.5 K or 166.5 C
