The amount of money in a bank account that is compounded yearly can be represented by the function A(y) = P(1 + r)y, where P is the amount initially deposited, r is the annual interest rate expressed as a decimal, and y is the number of years that have passed since the initial deposit. $2,700 was deposited 14 years ago into a bank account that is compounded yearly, and no additional deposits or withdrawals have been made. If the amount of money now in the bank account is $7,930.42, what is the annual interest rate?
A) about 5%
B) about 6%
C) about 7%
D) about 8%

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Answer:

The correct option is D. The interest is about 8%.

Step-by-step explanation:

The amount of money in a bank account that is compounded yearly can be represented by the function

[tex]A(y)=P(1+r)^y[/tex]

Where P is the amount initially deposited, r is the annual interest rate expressed as a decimal, and y is the number of years that have passed since the initial deposit.

The initial amount is $2700, numbers of years is 14 and the amount after 14 years is $7930.42.

[tex]7930.42=2700(1+r)^{14}[/tex]

[tex]2.937=(1+r)^{14}[/tex]

Taking log both sides.

[tex]log2.937=log(1+r)^{14}[/tex]        [tex](loga^b=bloga)[/tex]

[tex]0.4679=14log(1+r)[/tex]

[tex]0.033422=log(1+r)[/tex]

[tex]10^{0.033422}=10^{log(1+r)}[/tex]

[tex]1.079999=1+r[/tex]            [tex](10^{loga}=a)[/tex]                        

[tex]0.079999=r[/tex]

[tex]r\approx 0.08[/tex]

Therefore the correct option is D. The interest is about 8%.

Answer:

D

Step-by-step explanation:

7930.42 = 2700(1+r)¹²

(1+r)¹⁴ = 2.9371925926

14×ln(1+r) = ln2.9371925926

ln(1+r) = 0.076961016

1+r = e^0.076961016

1+r = 1.0799999729

r = 0.0799999729 × 100

= 8%

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