Question

The length of a rectangle is five times its width. If the perimeter is at most 96 centimeters, what is the greatest possible value for the width?

A) 2w+2 x (5w) <_ 96
B) 2w+2 x (5w) >_96
C) 2w+2 x (5w) < 96
D) 2w+2 x (5w) > 96

WILL GIVE BRAINLIEST!!!

Answer 1

Let width be W

Then length = 5W

P=2L+2W

P< 96cm

Then the Perimeter  of the rectangle is equal to

(2L+2W)< 96

2*(5W)+2W)≤96

Therefore, 2w+2⋅(5w)≤96

should be your answer