The ideal gas under STP is 22.4 L/mol. While the gas has a rule of P1V1/T1=P2V2/T2. So the volume under 101 kPa and 273 K is 0.2*22.4=4.48 L.
Answer: The volume of ideal gas is 3.32 L
Explanation:
To calculate the volume, we use the equation given by ideal gas equation:
[tex]PV=nRT[/tex]
where,
P = pressure of the gas = 200 kPa
V = Volume of gas = ?
n = number of moles of gas = 0.200 moles
R = Gas constant = [tex]8.31\text{L kPa }mol^{-1}K^{-1}[/tex]
T = temperature of the gas = 400 K
Putting values in above equation, we get:
[tex]200kPa\times V=0.200mol\times 8.31\text{L kPa }mol^{-1}K^{-1}\times 400K\\\\V=\frac{0.200\times 8.31\times 400}{200}=3.32L[/tex]
Hence, the volume of ideal gas is 3.32 L
