Question

HELP!!!!!!
If 3x−y=12, what is the value of 8x/2y?

A) 212
B) 44
C) 82
D) The value cannot be determined from the information given.

Answer 1

Answer:

Option A is correct.

The value of $\frac{8^x}{2^y}$ is; $2^{12}$

Step-by-step explanation:

Given, if  the equation: 3x -y = 12

Then find the value of $\frac{8^x}{2^y}$

we can write $\frac{8^x}{2^y}$ as:

$\frac{(2^3)^x}{2^y}$                     [ $8 = 2\times 2\times 2 = 2^3$ ]

$\frac{2^{3x}}{2^y}$                      [$(a^n)^m = a^{nm}$ ]

$2^{3x-y}$                                     [$\frac{a^n}{a^m} =a^{n-m}$ ]

Put the value of 3x -y =12

then we have;

$2^{12}$

Therefore, the value of $\frac{8^x}{2^y}$ is; $2^{12}$