Question

WILL MARK BRAINLIEST
Find the factorization for the polynomial 100x^2- 20x+1

A.) (50x+1)^2
B.) (10x+1)^2
C.) (10x-1)^2
D.)(50x-1)^2

Answer 1

Answer:

$\Large \boxed{\mathrm{\bold{C.}} \ (10x-1)^2}$

Step-by-step explanation:

$100x^2- 20x+1$

Rewriting -20x as -10x-10x.

$100x^2- 10x-10x+1$

Factoring the two groups.

$10x(10x-1)-1(10x-1)$

Taking (10x - 1) as a common factor.

$(10x-1)(10x-1)$

$(10x-1)^2$