Answer:
Yes , triangle DEF is congruent to JKL
Step-by-step explanation:
Given:
The coordinates of triangle DEF are;
D (2, 0)
E(5. 0)
F(5, 5)
and
the coordinates of triangle JKL are:
J(3, -7)
K(6, -7)
L (6, -2)
The rule of translation is used on triangle DEF to get triangle JKL:
[tex](x , y) \rightarrow (x+1 , y-7)[/tex]
i.e
[tex]D (2, 0) \rightarrow (2+1 , 0-7) = (3, -7)[/tex] = J
[tex]E (5, 0) \rightarrow (5+1 , 0-7) = (6, -7)[/tex] = K
[tex]F (5, 5) \rightarrow (5+1 , 5-7) = (6, -2)[/tex] = L
As, we know that two triangles are known as congruent if there is an isometry mapping one of the triangles to the other.
therefore, triangle DEF congruent to triangle JKL