What mass of sodium chloride (NaCl) forms when 7.5 g of sodium carbonate (Na2CO3) reacts with a dilute solution of hydrochloric acid (HCl)?
Next, cancel like terms and units. Which of the following shows the correct terms and units canceled?
First Option
Mass of sodium chloride (NaCl) forms when 7.5 g of sodium carbonate (Na2CO3) reacts with a dilute solution of hydrochloric acid (HCl) is 8.28g
Mass of sodium carbonate = 7.5 g
Mass of sodium chloride (NaCl) = ?
To find the grams and volume, the molecular weight of reactant as well as product must be calculated.
Accordingly, the molecular mass is as follows:
= 2 (Na) + 1 (C) + 3(O)
= 2 (23) + 1 (12) + 3 (16)
= 46 + 12 + 48
= 106 g/mol
= 2 (23 + 35.5)
= 2 (58.5)
= 117 g/mol
Weight of sodium chloride formed:As per the given chemical equation,
160 g of gives = 117 g of NaCl (1)
7.5 g of gives = 'X' g of NaCl (2)
When the equation 1 and 2 are cross multiplied it gives:
X × 106 = 117 × 7.5
X = 8.28g
Mass of sodium chloride (NaCl) forms when 7.5 g of sodium carbonate (Na2CO3) reacts with a dilute solution of hydrochloric acid (HCl) is 8.28g.
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