Respuesta :

For [tex]F[/tex] to be conservative, we need to have

[tex]\dfrac{\partial f}{\partial x}=\cos z[/tex]

[tex]\dfrac{\partial f}{\partial y}=10y[/tex]

[tex]\dfrac{\partial f}{\partial z}=-x\sin z[/tex]

Integrate the first PDE with respect to [tex]x[/tex]:

[tex]\displaystyle\int\frac{\partial f}{\partial x}\,\mathrm dx+\int\cos z\,\mathrm dx\implies f(x,y,z)=x\cos z+g(y,z)[/tex]

Differentiate with respect to [tex]y[/tex]:

[tex]\dfrac{\partial f}{\partial y}=10y=\dfrac{\partial g}{\partial y}\implies g(y,z)=5y^2+h(z)[/tex]

Now differentiate [tex]f[/tex] with respect to [tex]z[/tex]:

[tex]\dfrac{\partial f}{\partial z}=-x\sin z=-x\sin z+\dfrac{\mathrm dh}{\mathrm dz}\implies\dfrac{\mathrm dh}{\mathrm dz}=0\implies h(z)=C[/tex]

So we have

[tex]f(x,y,z)=x\cos z+5y^2+C[/tex]

so [tex]F[/tex] is indeed conservative.

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