Answer:
3 (2x-5)(x+2)
Step-by-step explanation:
We are given the following quadratic expression:
[tex]6x^2-3x-30[/tex]
and we are to solve this by factorizing.
For that, we will take 3 as a common and factorize the rest of the expression.
[tex]6x^2-3x-30[/tex]
[tex]3(2x^2-x-10)[/tex]
Findinf factors of [tex](2x^2-x-10)[/tex] such that when multiplied they give a product of -20 and when added they give a result of -1:
[tex]3(2x^2+4x-5x-10)\\\\3((2x(x+2)-5(x+2))\\\\3(2x-5)(x+2)[/tex]
Therefore, the factors of the given expression [tex]6x^2-3x-30[/tex] are [tex]3(2x-5)(x+2)[/tex].
