Respuesta :

The given solution is a mixture of [tex]NaHCO_{3}[/tex]and [tex]Na_{2}CO_{3}[/tex]. It acts as a buffer as it is a combination of the weak acid [tex]HCO_{3}^{-}[/tex]and it's conjugate base [tex]CO_{3}^{2-}[/tex].

[tex][Acid] = [HCO_{3}^{-}]=1.0 M[/tex]

[tex][Base] =[CO_{3}^{2-}]=0.1 M[/tex]

pH of the buffer solution can be calculated from Hendersen-Hasselbalch equation as below:

[tex]pH=pK_{a}+log\frac{[CO_{3}^{2-}]}{[HCO_{3}^{-}]}[/tex]

[tex]pH=10.33+log\frac{0.1}{1.0}[/tex]

pH = 10.33+(-1)

     = 9.33


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