The given solution is a mixture of [tex]NaHCO_{3}[/tex]and [tex]Na_{2}CO_{3}[/tex]. It acts as a buffer as it is a combination of the weak acid [tex]HCO_{3}^{-}[/tex]and it's conjugate base [tex]CO_{3}^{2-}[/tex].
[tex][Acid] = [HCO_{3}^{-}]=1.0 M[/tex]
[tex][Base] =[CO_{3}^{2-}]=0.1 M[/tex]
pH of the buffer solution can be calculated from Hendersen-Hasselbalch equation as below:
[tex]pH=pK_{a}+log\frac{[CO_{3}^{2-}]}{[HCO_{3}^{-}]}[/tex]
[tex]pH=10.33+log\frac{0.1}{1.0}[/tex]
pH = 10.33+(-1)
= 9.33