So since we already have one of the unknowns equaling something, we start by substituting...
y= 3x so let's substitute 3x into the first equation where the y is...
y = 2x + 2
3x = 2x + 2
subtract 2x from each side
x = 2
So now we know x = 2 So we can now substitute it back into the equation but for x this time...
y = 2x + 2
y = 2(2) + 2
y = 4 + 2 = 6
So our solution set is
(2, 6)
You can check it by substituting x and y into both of the equations to see if you have a true statement...
y= 2x + 2
6 = 2×2 + 2
6 = 6
y = 3x
6 = 3×2
6 = 6
Both true so it checks!
*note- I noticed that my solution was not one of your options, but if you substitute the available option that you gave into the equations none of them work, so take a look at your possible answers and see if you didn't leave something out. ;)
