Respuesta :
ANSWER
The explicit formula that defines the sequence is
[tex]f(n) = 3 ( \frac{1}{3} ) ^{n - 1} [/tex]
EXPLANATION
The given sequence is
[tex]3,1, \frac{1}{3} , \frac{2}{9} ,...[/tex]
The first term of this sequence is
[tex]a = 3[/tex]
We can find the common ratio by expressing a subsequent term over a previous term and simplifying it.
The common ratio is
[tex]r = \frac{1}{3} [/tex]
The formula for finding the nth term of the given geometric sequence is given by,
[tex]f(n) = a {r}^{n - 1} [/tex]
We now substitute the value of the first term and the common ratio in to the above formula to obtain,
[tex]f(n) = 3( \frac{1}{3} )^{n - 1} [/tex]
The correct answer is option D.
The explicit formula that defines the sequence is
[tex]f(n) = 3 ( \frac{1}{3} ) ^{n - 1} [/tex]
EXPLANATION
The given sequence is
[tex]3,1, \frac{1}{3} , \frac{2}{9} ,...[/tex]
The first term of this sequence is
[tex]a = 3[/tex]
We can find the common ratio by expressing a subsequent term over a previous term and simplifying it.
The common ratio is
[tex]r = \frac{1}{3} [/tex]
The formula for finding the nth term of the given geometric sequence is given by,
[tex]f(n) = a {r}^{n - 1} [/tex]
We now substitute the value of the first term and the common ratio in to the above formula to obtain,
[tex]f(n) = 3( \frac{1}{3} )^{n - 1} [/tex]
The correct answer is option D.