the pressure of a gas p(v) varies inversely with the volume of gas v. the pressure of a gas measures 8kg/cm^2 when its volume is 40cm^3.

which equation can be used to find the pressure of the gas when its volume is changed.

A. p(v)=320v
B. p(v)=320 over v
C. p(v)=5v
D. p(v)=5 over v

Respuesta :

Answer:

B

Step-by-step explanation:

Since p and v vary inversely then the equation relating them is

p = [tex]\frac{k}{v}[/tex] ← k is the constant of variation

to find k use the condition p = 8 when v = 40

k = pv = 8 × 40 = 320

⇒ p(v) = [tex]\frac{320}{v}[/tex] → B


Answer:

B.[tex]p(v)=\frac{320}{v}[/tex]

Step-by-step explanation:

We are given that

The pressure of gas p(v) varies inversely with the volume of gas v.

Pressure of gas measures=[tex]8kg/cm^3[/tex]

Volume of gas=[tex]40cm^3[/tex]

We have to find the equation that can be used to find the pressure of the gas when its volume is changed.

According to question

p(v)[tex]\propto\frac{1}{v}[/tex]

[tex]p(v)=\frac{k}{v}[/tex]

Where k=proportionality constant

Substitute the given values then, we get

[tex]8=\frac{k}{40}[/tex]

[tex]k=8\times 40=320[/tex]

Substitute the value of k then, we get

[tex]p(v)=\frac{320}{v}[/tex]

Hence,option B is true.

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