Slope-intercept form is:
y = mx + b
"m" is the slope, "b" is the y-intercept (the y value when x = 0)
You need to find "m" and "b". Since you know "m" is -1/3, you can plug it into the equation.
y = mx + b
y = -1/3x + b
To find "b", you can plug in the point (-5,5) into the equation.
y = -1/3x + b
5 = -1/3(-5) + b
5 = 5/3 + b Subtract 5/3 on both sides
5 - 5/3 = b Make the denominators the same in order to subtract them
15/3 - 5/3 = b
10/3 = b
[tex]y=-\frac{1}{3}x+\frac{10}{3}[/tex]
Answer:
y = -1/3x + 10/3
Step-by-step explanation:
Hi there,
We are given that a line contains the point (-5, 5) and the slope -1/3
We want to find the equation of the line that contains this point & slope
There are 3 ways to write the equation of the line, with the most common way being slope-intercept form, which is y=mx+b, where m is the slope and b is the value of y at the y intercept
First, as we are immediately given the slope of the line, we can substitute that as m in y=mx+b.
y=-1/3x+b
Now we need to find b
As the equation passes through the point (-5,5), we can use it to help solve for b.
Substitute -5 as x and 5 as y.
5 = -1/3(-5)+b
Multiply
5 = 5/3 + b
subtract 5/3 from both sides
10/3 = b
Substitute 10/3 as b into the equation
y = -1/3x + 10/3
Hope this helps!
Topic: equation of the line
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