Question

You are balancing an ionic compound. Let's call it: AB.

Ion A has a charge of +2 and Ion B has a charge of -3.

Therefore, you determine that the ionic compound (AB) will have a ratio of 3 As for every 2 Bs.

How would you modify AB in order to show that they have this 3-to-2 ratio? Question 2 options: 3A2B A3B2 A3B2

Answer 1

Answer:- $A_3B_2$

Explanations:- It is given that the charge for A is +2 and the charge for B is -3. The over all compound is neutral means the over all charge is zero. For making the over all charge zero, we need 3 positive ions and 2 negative ions. This makes a +6 charge for A and -6 charge for B and the over all charge is zero.

Also, if we think about the criss cross then charge of A becomes the subscript of B and the charge of B becomes the subscript of A.

So, the formula of the ionic compound is $A_3B_2$ . In this compound the ratio of A to B is 3:2.

The balanced equation could be shown as:

$3A+2B\rightarrow A_3B_2$

Answer 2

Answer:

A3B3

Explanation:

I TOOK THE TEST ;P