Hello from MrBillDoesMath!
Answer: (4b-6) log(a) = log (3c + d)
Discussion:
Take the log of both sides of the equation:
log ( a ^(4b-6)) = log (3c + d)
As the log functions causes exponents to become multiplexers, this equation is the same as
(4b-6) log(a) = log (3c + d)
Thank you,
MrB
