Question

What is the solution to 3x^2+3x+5=0? What are the zeroes of y=x^2-4x-5?

Answer 1

Answer:

3. Fourth option

4. Fourth option

Step-by-step explanation:

3.

$3x^2 +3x +5 = 0\\x = \dfrac{-3 \pm \sqrt{9 - 4(3)(5)}}{6}\\x = \dfrac{-3 \pm \sqrt{-51}}{6}\\x = \dfrac{-3 \pm i\sqrt{51}}{6}$

4.

$x^2 - 4x -5 = 0\\(x -5)(x +1) = 0\\x = 5, -1$