Given:
Molecules of O2 at STP = 4.9 * 10²⁴
STP conditions implies-
Temperature T = 273 K
Pressure = 1 atm
To determine:
The volume (V) of O2
Explanation:
Based on the ideal gas equation:
PV = nRT-----(1)
where n = number of moles of O2
R = gas constant = 0.0821 L.atm/mol-K
Now, 1 mole of O2 corresponds to 6.023*10²³ molecules
# moles of O2 corresponding to the given molecules=
= 4.9*10²⁴ molecules O2 * 1 mole O2/6.023*10²³ molecules = 8.135 moles
From equation(1) we have:
V=nRT/P = 8.135*0.0821*273/1 = 182.3 L
Ans: Volume of O2 under the given conditions is 182.3 L
