Answer:
[tex]6\frac{3}{8}[/tex] feet.
Step-by-step explanation:
We have been that Jebb is the tallest player on his basketball team. He is 1 1/2 times as tall as the shortest girl in sixth grade, who is 4 1/4 feet tall.
Let us find height of Jebb by multiplying [tex]1\frac{1}{2}[/tex] by [tex]4\frac{1}{4}[/tex].
First of all we will convert our mixed fractions into improper fractions.
[tex]1\frac{1}{2}=\frac{3}{2}[/tex]
[tex]4\frac{1}{4}=\frac{17}{4}[/tex]
[tex]\text{Jebb's height}=\frac{3}{2} \times\frac{17}{4}[/tex]
[tex]\text{Jebb's height}=\frac{51}{8}=6\frac{3}{8}=6.375[/tex]
Therefore, Jebb is [tex]6\frac{3}{8}[/tex] feet tall.