Question

What are the zeros of the quadratic function f(x)=2x^2+8x-3

Answer 1

Answer:

you can use the quadratic formula to get theses:-

x  =[-8 +/- sqrt(8^2 - 4*2*-3)]  / 4

= -2 +/- sqrt88) / 4

= 0.35, -4.35   to nearest hundredth

Step-by-step explanation: