Answer:
[tex]y=10000(1.015)^{12t}[/tex]
option-B......Answer
Step-by-step explanation:
We are given
amount taken for loan =$10000
so, P=10000
annual interest rate =18%
r=0.18
now, we can use formula
[tex]y=P(1+\frac{r}{n} )^{nt}[/tex]
Since, it is compounded monthly
so, n=12
we can plug values
[tex]y=10000(1+\frac{0.18}{12} )^{12t}[/tex]
[tex]y=10000(1.015)^{12t}[/tex]