Answer: NT is congruent to NS.
Step-by-step explanation:
Since, we know that in a triangle, If a diameter (or radius) is perpendicular to a chord, then it bisects the chord and its arc.
Here, In circle C, chord ST is perpendicular to radius CB and also ST and CB intersect at point N.
Therefore, by the above property, radius CB must bisect the chord ST at N.
⇒ NS = NT.
Thus, NS is congruent to NT. ( By the property of congruence)
