Question

Bill reads 1/5 of a book on Monday he reads 2/3 of the book on Tuesday if he finishes reading the book on Wednesday or fraction of the book did he read on Wednesday

Answer 1

Answer:

$\frac{2}{15}$

Step-by-step explanation:      

We have been given that Bill reads 1/5 of a book on Monday he reads 2/3 of the book on Tuesday.

Let x be the part of book that Bill read on Wednesday. We can find x by equating the sum of parts of book read on each day by 1.  

$\frac{1}{5}+\frac{2}{3}+x=1$

First of all we will find a common denominator.

$\frac{1\times 3}{5\times 3}+\frac{2\times 5}{3\times 5}+x=1$

$\frac{3}{15}+\frac{10}{15}+x=1$

$\frac{3+10}{15}+x=1$

$\frac{13}{15}+x=1$

$x=1-\frac{13}{15}$

$x=\frac{15-13}{15}$  

$x=\frac{2}{15}$

Therefore, Bill read $\frac{2}{15}$ of the book on Wednesday.  

Answer 2

Bill read $\frac{2}{15}$ of the book on Wednesday.

Learn More

Given:

Bill reads $\frac{1}{5}$ of a book on Monday

     reads$\frac{2}{3}$ of the book on Tuesday

     finish book on Wednesday.

Question:

Fraction of the book did he read on Wednesday?

We can say that on Wednesday Bill read 'x' of the book. The total book he reads would be 1, so we can write as follow

Book read on Wednesday = Total book - part  of the book read on Monday- part of the book read on Tuesday

$\boxed { = 1 - \frac{1}{5} - \frac{2}{3} }$

To be able to subtract those fraction, we need to find the common denominator for 5 and 3 which is 15. We then can write 1 = $\frac{15}{15}$

$\boxed {= \frac{15}{15} - (\frac{1 \times3}{5 \times3}) -(\frac{2 \times5}{3 \times5}) }  \\ \boxed {= \frac{15-3-10}{15} }\\\boxed {= \frac{2}{15} }$

so Bill reads $\frac{2}{15}$ of the book on Wednesday

Learn More

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Keyword: mixed fraction, subtraction, improper fraction, part to whole relationship, grouping, mixed fraction additional, subtraction fraction