Question

if the momentum of the NASA space shuttle as it leaves the atmosphere is 3.75 x 10^8 kg*m/s and its mass is 7500 kg what is its speed

Answer 1

speed equal distance divided by time that should help

Answer 2

Answer:

Velocity of the space velocity, v = 50,000 m/s

Explanation:

It is given that,

The momentum of the NASA space shuttle as it leaves the atmosphere is, $p=3.75\times 10^8\ kgm/s$

Mass of the space shuttle, m = 7500 kg

We need to find the speed of the NASA space. The momentum of an object is given by the product of mass of the object and its velocity.

p = mv

$v=\dfrac{p}{m}$

$v=\dfrac{3.75\times 10^8\ kgm/s}{7500\ kg}$

v = 50,000 m/s

So, the speed of the NASA space shuttle is 50,000 m/s. Hence, this is the required solution.