3) 490 meters
The vertical motion of the supplies is an accelerated motion with constant acceleration g=-9.8 m/s^2, so its vertical position is given by
[tex]y(t)=h+\frac{1}{2}gt^2[/tex]
where h is the initial height of the airplane, and t is the time taken. Substituting y(t)=0 and t=10 s (when the supplies reach the ground), we find the height h:
[tex]0=h+\frac{1}{2}gt^2\\h=-\frac{1}{2}gt^2=-\frac{1}{2}(-9.8 m/s^2)(10 s)^2=490 m[/tex]
4) 65 m/s
The horizontal motion of the supplies is a uniform motion with constant speed v, which is given by the ratio between the distance travelled and the time taken:
[tex]v=\frac{d}{t}=\frac{650 m}{10 s}=65 m/s[/tex]
5) True
A projectile has two independent motions:
- A horizontal motion, which is a uniform motion with constant horizontal speed
- A vertical motion, which is an accelerated motion with constant acceleration equal to the gravitational acceleration (g=9.8 m/s^2) directed downward
6) False
The trajectory of a projectile is a parabola, which is the composition of the two independent motions along the horizontal and vertical directions.
7) The vertical component always equals the horizontal component.
This statement is false. In fact, the horizontal component of the velocity of a projectile is:
[tex]v_x = v_0 cos \theta[/tex]
while the vertical component of the initial velocity of the projectile is
[tex]v_y = v_0 sin \theta[/tex]
So, we see that they are not always equal.
8) constant
In fact, there are no forces acting along the horizontal direction of the projectile's motion: therefore, the horizontal acceleration is zero, and so the horizontal velocity is constant.