Answer:
Option B is correct.
The value of x is, 0
Step-by-step explanation:
Given the system of equation:
-x+2y =6 .....[1]
6y =x+18 ......[2]
We can write equation [1] as;
-x = 6-2y or
x = -6 + 2y ......[3]
Substitute equation [3] in [2] we get;
6y =-6 + 2y + 18
or
6y = 2y +12
Subtract 2y from both sides we get;
6y -2y = 2y+ 12 -2y
Simplify:
4y = 12
Divide both sides by 4 we get;
[tex]\frac{4y}{4} =\frac{12}{4}[/tex]
Simplify:
y =3
Substitute the value of y in equation [3] to solve for x;
x = -6 + 2(3)
x = -6 +6 = 0
Therefore, the value of x is, 0
Answer:
For those of you doing unit 7 lesson 2 solving systems using substitution questions 1-4
Step-by-step explanation:
1. A
2. C
3. C
4. D
