The problem gives you the formula for the volume of a cone - you just need to find the values for the variables. In this case, we can see [tex]h = 6[/tex] and [tex]r = 5[/tex]. Thus, by using the formula with [tex]\pi \approx 3.14[/tex], we can solve for the volume [tex]V[/tex]:
[tex]V \approx \dfrac{1}{3} (3.14) (5^2) (6)[/tex]
[tex]V \approx 157[/tex]
The volume is approximately 157 ft.
