Question

What is a difference is squares that has a factor of x+8? Complete the expression

Answer 1

$\bf \textit{difference of squares} \\\\ (a-b)(a+b) = a^2-b^2 ~\hfill (x+8)\boxed{(x-8)}\implies x^2-8^2\implies x^2-64 \\\\\\ ~\hspace{34em}$

Answer 2

Answer:

$(x^2-8^2)$

Step-by-step explanation:

Here the question is asking to determine the difference of the squares , which has (x-8) has one of the factor.

Let us understand the formula for difference of the squares

$a^2-b^2=(a+b)(a-b)$

Here we can see that (a-b) is a factor of difference of squares too. Hence we substitute the values of a as x and b as 8 to find the answer.

$x^2-8^2=(x+8)(x-8)$

Hence our answer is $x^2-8^2$ as it has (x-8) as one of its factor and it is a difference of squares .