Question

The price per night for a hotel room is different at three hotels. Which hotel cost the least per night

Answer 1

$455 \div 7 = 65$
per night

300÷5=60 per night

192÷3=64 per night

hotel B cost less

Answer 2

According to the prices of the hotel room for the sum up days, the amount that is least price of the hotel room per day is Hotel B.

The price of the hotel room for per day can be calculated as:

$\text{Per day Room Price} =\dfrac{\text{Total Price}}{\text{Number of nights}}$

For A:

$\text{Per day Room Price} = \dfrac{\ 192}{3}\\\text{Per day Room Price} = \ 64$

For B:

$\text{Per day Room Price} = \dfrac{\ 300}{5}\\\text{Per day Room Price} = \ 60$

For C:

$\text{Per day Room Price} = \dfrac{\ 455}{7}\\\text{Per day Room Price} = \ 65$

After comparing all the three prices of the hotel rooms, the least cost of the hotel room is $60.

Therefore, hotel B cost least per night.

To know more about the prices of hotel rooms, refer to the link below:

https://brainly.com/question/6545652