Respuesta :

[tex]\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{9})\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{-2}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-2-9}{4-0}\implies \cfrac{-11}{4} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-9=-\cfrac{11}{4}(x-0) \\\\\\ y-9=-\cfrac{11}{4}x\implies y=-\cfrac{11}{4}x+9[/tex]

Answer:

The slope intercept form is y= -11/4x +9

Step-by-step explanation:


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