[tex]\bf \begin{cases} y=\cfrac{1}{2}x+\cfrac{3}{2}\\\\ \boxed{y}=2x-3 \end{cases}~\hspace{5em}\stackrel{\textit{using substitution}}{\boxed{2x-3}=\cfrac{1}{2}x+\cfrac{3}{2}} \\\\\\ \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{2}}{2(2x-3)=2\left( \cfrac{1}{2}x+\cfrac{3}{2} \right)}\implies 4x-6=x+3\implies 3x=9[/tex]
[tex]\bf x=\cfrac{9}{3}\implies \blacktriangleright x=3 \blacktriangleleft \\\\\\ \stackrel{\textit{using the found \underline{x} in the 2nd equation}}{y=2(3)-3\implies y=6-3}\implies \blacktriangleright y=3 \blacktriangleleft[/tex]
what does the solution mean? check the picture below.
