Myron is cooking meat. The double number line shows that he needs 1212 hours to cook 55 kilograms of meat. Based on the ratio shown in the double number line, how long does Myron need to cook 33 kilograms of meat?

Respuesta :

Answer:  He needs 20 hours for making 33 kg of meat.

Step-by-step explanation:

Since,  if a a thing in quantity [tex]x_1[/tex] takes time [tex]t_1[/tex] and that thing in quantity [tex]x_2[/tex] takes time [tex]t_2[/tex]

Then, we know that,

[tex]x_1\times t_1=x_2\times t_2[/tex]

[tex]\frac{x_1}{x_2} = \frac{t_2}{t_1}[/tex]

Here, [tex]x_1=55[/tex] kg, [tex]t_1=12[/tex] hours, [tex]x_2= 33[/tex] kg and [tex]t_2=?[/tex]

Thus, [tex]\frac{55}{33} = \frac{t_2}{12}[/tex]

⇒[tex]t_2=\frac{55}{33}\times 12[/tex]

⇒[tex]t_2=\frac{5}{3}\times 12[/tex]

⇒[tex]t_2=20[/tex]

Thus, he needs 20 hours to make 33 kg of meat.

Answer:

20 Hours to cook 33 kilograms of meat.

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