Answer: The density of the block is estimated to be [tex]0.30 g/cm^3[/tex].
Explanation:
Density of the water,[tex]\rho_w=1.0 g/cm^3[/tex]
Buoyant force = [tex]\rho\times volume\times g[/tex]
g = gravitational acceleration
volume of the block = v
density of the block =[tex]\rho_o[/tex]
Weight of the Block = Buoyant force exerted by water
[tex]rho_o\times v\times g=\rho_w\times 30\%\text{of volume of block}\times g[/tex]
[tex]\rho_o\times v\times g=\rho_w\times 0.30v\times g[/tex]
[tex]\rho_o\times v\times 9.8 m/s^2=1 g/cm^3\times 0.30v\times 9.8 m/s^2[/tex]
[tex]\rho_o=0.30 g/cm^3[/tex]
The density of the block is estimated to be [tex]0.30 g/cm^3[/tex].
