Question

How do you solve this by using square roots?

$2(x-2)^2-8=-4$

Answer 1

Answer:

x = 2 ± $\sqrt{2}$

Step-by-step explanation:

isolate (x - 2)² by adding 8 to both sides and dividing by 2

2(x - 2)² = 4

(x - 2)² = 2 ( take the square root of both sides )

$\sqrt{(x-2)^2}$ = ± $\sqrt{2}$

x - 2 = ± $\sqrt{2}$ ( add 2 to both sides )

x = 2 ± $\sqrt{2}$ ← solutions