If YWZ ~ YXW, what is true about XWZ?

Answer:
B.
Step-by-step explanation:
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Answer:
The correct option is 2.
Step-by-step explanation:
It is given that ΔYWZ ~ ΔYXW.
ΔYWZ is a right angled triangle. In a right angled triangle the sum of two non right angled is 90°.
Let the measure of ∠YWZ be x°, so the measure of ∠YZW is (90-x)°.
The corresponding angles of two similar triangles are equal.
Since ΔYWZ ~ ΔYXW, therefore
[tex]\angle YWZ=\angle YXW=x^{\circ}[/tex]
[tex]\angle YZW=\angle YWX=(90-x)^{\circ}[/tex]
[tex]\angle WYZ=\angle XYW=90^{\circ}[/tex]
From the given figure it is clear that the angle XWZ is the sum of angles XWY and YWZ.
[tex]\angle XWZ=\angle XWY+\angle YWZ[/tex]
[tex]\angle XWZ=(90-x)^{\circ}+x^{\circ}[/tex]
[tex]\angle XWZ=(90)^{\circ}-(x)^{\circ}+x^{\circ}[/tex]
[tex]\angle XWZ=(90)^{\circ}[/tex]
The measure of angle XWZ is 90°. So, the angle XWZ is a right angle.
Therefore the correct option is 2.