Question

If a vector's magnitude is 32 units right and 28 units up, what's the approximate magnitude of a vector that's one-fourth the length of the first vector?

Answer 1

Answer:

10.6 units

Step-by-step explanation:

First of all, let's find the magnitude of the first vector, which is given by the resultant of its two components:

$R=\sqrt{32^2+28^2}=42.5$ units

The second vector has a length which is 1/4 of the length of the first vector, so it is

$R'=\frac{1}{4}R=\frac{1}{4}(42.5)=10.6$ units