Question

A 7.5 kg cannon ball leaves a canon with a speed of 185 m/s. Find the average net force applied to the ball if the cannon muzzle is 3.6 m long.

Answer 1

We would like to know the average net force. Therefore, we can calculate the acceleration using:

x = 0.5*a*t^2

v = a*t

where x=3.6m and v=185 m/s.

Therefore,

t=v/a     and hence    x = 0.5*a*(v/a)^2 = 0.5 * (v^2)/a

so    a= (0.5*v^2)/x

Since we know the values for v and x, as written above, we can calculate a by plugging the numbers in.

The average net force will then be:

F = m*a,

where m=7.5kg.

Answer 2

Answer:

The average net force applied on the ball is $33274.30\;\rm{N$.

Explanation:

Given: A $7.5\;\rm{kg$ cannon ball leaves a canon with a speed of $185\;\rm{m/s$.

Calculating the acceleration using the formula: $a=\frac{v}{t}\;\&\;s=\frac{1}{2}at^2$

  $s=\frac{1}{2}\frac{v^2}a$

$3.6=\frac{0.5\times{(185)}^2}{a}$

  $a=4753.477\;\rm{ms^{-2}$

Now, using the average net force formula: $F=ma$

$F=7.5\times4753.477\\F=33274.30\;\rm{N$

Hence, the average net force applied on the ball is $33274.30\;\rm{N$.

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