Find the equation of a parabola with its vertex at the origin and a focus of (-8,0)
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the equation of a parabola with its vertex at the origin and a focus of (-8,0)
vertex is (0,0), h=0 and k=0
Focus is (-8,0)
Focus is (h+p, k)
We know h=0 and k=0
(0+p, 0) is (-8,0)
p = -8
General form of equation is
[tex](y-k)^2=4p(x-h)[/tex]
h=0, k=0 and p =-8
[tex](y-0)^2=4(-8)(x-0)[/tex]
[tex]y^2= -32x[/tex]
Answer : option A