Assume a quarter, diameter 0.96 inches, is centered at the point (–2, 5), where each unit represents one inch. Write the equation of a circle that would precisely enclose the coin.
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Answer:
[tex](x+2)^{2}+(y-5)^{2}=0.2304[/tex]
Step-by-step explanation:
we know that
The equation of a circle into center radius form is equal to
[tex](x-h)^{2}+(y-k)^{2}=r^{2}[/tex]
where
(h,k) is the center of the circle
r is the radius of the circle
In this problem we have
[tex]r=Diameter/2=0.96/2=0.48\ in[/tex]
[tex](h,k)=(-2,5)[/tex]
substitute
[tex](x+2)^{2}+(y-5)^{2}=0.48^{2}[/tex]
[tex](x+2)^{2}+(y-5)^{2}=0.2304[/tex]