Respuesta :
Any integer (not a fraction) that cannot be divided exactly by 2 is an odd integer.
So, we have ( 2k + 1 ) + ( 2k + 3 ) = 264, where 2k + 1 and 2k + 3 are the two consecutive positive odd integers ( k > 0 );
Then, 4k + 4 = 264;
4k = 260;
k = 65;
2k + 1 = 131;
2k + 3 = 133;
The chosen numbers are 131 and 133.
odd integers are 2 apart (1,3,5,7, etc)
odd integers can be reprsented in the form 2n+1 or 2n-1 where n is an integer
so 2 consecutive integers can be represented as 2n-1 and 2n+1 (2 apart)
their sum (add) is 264
2n-1+2n+1=264
4n=264
divide both sides by 4
n=66
the numbers are 2n-1 and 2n+1
2n-1=2(66)-1=132-1=131
2n+1=2(66)+1=132+1=133
the 2 integers rae 131 and 133