help please I get y=mx+b but I'm not sure how to do this

(3,4) (9,7)
to find the slope
m = (y2-y1)/(x2-x1)
= (7-4)/(9-3)
3/6
1/2
The slope is 1/2
point slope form
y-y1 = m(x-x1)
y-4 = 1/2(x-3)
distribute
y-4 = 1/2x -3/2
add 4 to each side
y = 1/2 x -3/2 + 4
y = 1/2 x -3/2 + 8/2
y = 1/2 x + 5/2
this is in slope intercept form
y = [tex]\frac{1}{2}[/tex] x + [tex]\frac{5}{2}[/tex]
the equation of a line in slope-intercept form is
y = mx + c ( m is the slope and c the y-intercept )
to calculate m use the gradient formula
m = ( y₂ - y₁ ) / (x₂ - x₁ )
with (x₁, y₁ ) = (3, 4 ) and (x₂, y₂ ) = (9, 7 )
m = [tex]\frac{7-4}{9-3}[/tex] = [tex]\frac{3}{6}[/tex] = [tex]\frac{1}{2}[/tex]
y = [tex]\frac{1}{2}[/tex] x + c ← is the partial equation
to find c substitute either of the 2 points into the partial equation
using (3, 4 ) then
4 = [tex]\frac{3}{2}[/tex] + c ⇒ c = [tex]\frac{5}{2}[/tex]
y = [tex]\frac{1}{2}[/tex] x + [tex]\frac{5}{2}[/tex] ← equation in slope-intercept form