Question

A gas has an initial volume of 455 mL at 105ºC and a final volume of 235 mL. What is its final temperature in Celsius degrees?

Answer 1

$\frac{V1}{V2} = \frac{T1}{T2} \\ \frac{455}{235} = \frac{378}{x} \\ x = \frac{235 \times 378}{455} \\ x = 195 \: K \\ K=273+°C \\ 195 = 273 + °C \\ 195 - 273 = °C \\ T \: = - 78 \: °C$