Let f(x) =x+1 and g(x)=1/x. The graph of (f o g)(x) is shown below. What is the range of (f o g)(x)?
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Answer:
all real numbers except y=1
Step-by-step explanation:
[tex]f(x)=x+1[/tex]
[tex]g(x)=\frac{1}{x}[/tex]
[tex](f og)(x)= f(g(x))[/tex]
Plug in 1/x for g(x)
[tex](f og)(x)= f(g(x))=f(\frac{1}{x})[/tex]
Now we plug in the fraction in f(x)
[tex](f og)(x)= f(g(x))=f(\frac{1}{x})=\frac{1}{x}+1[/tex]
Range of the function are the y values for which the function is defined
In the graph , we can see that the graph goes close to y=1 but does not cross y=1
So range is all real numbers except y=1