Adult male heights are normally distributed with a mean of 70 inches and a standard deviation of 3 inches the average basketball player is 79 inches tall approximately what percent of the adult male population is taller than the average basketball player

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your correct answer should be:         z = (x - mean) / SD = (79 - 70) / 3 = 3  

P (Z > 3)? = 1 - F (z) = 1 - F (3) = 0.00135            i hope this is helpful! :D

Answer: 0.135

Step-by-step explanation:

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